MHT CET202210 Aug 2022Morning ShiftPhysicsElectromagnetic InductionActual
A toroid is a long coil of wire ( N turns) wound over a circular core. The coefficient of self-induction of the toroid is [The magnetic field in it is uniform and R>>r , where r= radius of wire, R= radius of coil] ( ₀= permeability of free space )
Options
- A₀ N^2 R^2 2 r
- B₀ N r 2 R
- C₀ N^2 r^2 R
- D₀ N^2 r^2 2 R
Correct answer
D. ₀ N^2 r^2 2 R
Step-by-step solution
We know relation between the flux and the induction is: L= I Flux through the given area A with magnetic field B is given by, =N A B The field at the center of the toroid is given by B= ₀ n I , where aligned & n= N 2 R & =N ( r^2 ) [ ₀ ( N 2 R ) I ] & = ₀ N^2 r^2 I 2 R aligned Using the definition of self-induction: L= I = ₀ N^2 r^2 2 R