The network shown in the figure is part of complete circuit. If at a certain instant the current i is 5 ~A and is decreasing at the rate of 10^3 ~A / s , then V _ B - V _ A is

Step-by-step solution

Consider the diagram below: Given, =5 ~A , R =1 , L =5 mH , di dt =10^3 ~A / s aligned & V_A-i R+E-L ( d i d t )=V_B & V_A-V_B= (i R+L ( d i d t )-E ) aligned aligned & V _ A - V _ B =5 ~A 1 +5 10⁻³ H 10⁻³ A s -15 ~V & ~V _ B - V _ A =-(5+5-15) V =5 ~V aligned