MHT CET202124 Sep 2021Morning ShiftPhysicsElectromagnetic InductionActual
A circuit has self-inductance ' L ' and carries a current ' I '. To prevent sparking when the circuit is switched off, a capacitor which can withstand potential difference ' V ' is used. The least capacitance is
Options
- AIV L
- BL ( V L )^2
- CL ( I V )^2
- DLI V
Correct answer
C. L ( I V )^2
Step-by-step solution
The energy stored in the inductance is given by U = 1 2 LI ^2 Energy stored by the capacitor is given by W = 1 2 CV ^2 This energy must be transferred to the capacitor. aligned & 1 2 CV ^2= 1 2 LI ^2 & C = L ( I V )^2 aligned