MHT CET202122 Sep 2021Morning ShiftPhysicsElectromagnetic InductionActual
A circular coil of radius ' R ' has ' N ' turns of a wire. The coefficient of self-induction of the coil will be ( ₀= permeability of free space)
Options
- A₀ N R^2 2
- B₀ ~N R 4
- C₀ N^2 R 2
- D₀ ~N R 2
Correct answer
C. ₀ N^2 R 2
Step-by-step solution
Magnetic field at the center of the coil is given by B = ₀ NI 2 R Magnetic flux linked to the coil is aligned & = NBA = ₀ ~N ^2 I 2 R R ^2= ₀ ~N ^2 RI 2 & ~L = I = ₀ ~N ^2 R 2 aligned