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MHT CET202122 Sep 2021Morning ShiftPhysicsElectromagnetic InductionActual

A wire of length 1 ~m is moving at a speed of 2 ~m / s perpendicular homogenous magnetic field of 0.5 ~T . The ends of the wire are joined to resistance 6 . The rate at which work is being done to keep the wire moving at that speed is

Options

  1. A1 3 ~W
  2. B1 6 ~W
  3. C1 12 ~W
  4. D1 ~W

Correct answer

B. 1 6 ~W

Step-by-step solution

Emf induced e = B v =0.5 1 2=1 ~V Rate of doing work = Power P = e ^2 R = (1)^2 6 = 1 6 ~W

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