MHT CET202120 Sep 2021Evening ShiftPhysicsElectromagnetic InductionActual
A straight conductor of length 0.6 ~m is moved with a speed of 10 ~ms ⁻¹ perpendicular to magnetic field of induction 1.2 weber m ⁻² . The induced e.m.f. across the conductor is
Options
- A6 ~V
- B7.2 ~V
- C0.72 ~V
- D12 ~V
Correct answer
B. 7.2 ~V
Step-by-step solution
The induced emf is given by E = B v =1.2 0.6 10=7.2 ~V