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MHT CET202120 Sep 2021Evening ShiftPhysicsElectromagnetic InductionActual

An inductor coil wound uniformly has self-inductance ' L ' and resistance ' R '. The coil is broken into two identical parts. The two parts are then then connected in parallel across a battery of ' E ' volt of negligible internal resistance. The current through battery at steady state is

Options

  1. A2 E R
  2. B3 E R
  3. C4 E R
  4. DE R

Correct answer

C. 4 E R

Step-by-step solution

In DC, there is no use of inductance. Since the coil is broken into two identical points, each part will have resistance R 2 . When these are connected in parallel, their equivalent resistance will be R 4 . Hence the current I is given by = E R / 4 = 4 E R

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