MHT CET202120 Sep 2021Morning ShiftPhysicsElectromagnetic InductionActual
A metal conductor of length 1 ~m rotates vertically about one of its ends at an angular velocity of 5 rad / s . if horizontal component of earth's magnetic field is 0.2 10⁻⁴ ~T , then the e.m.f. developed between the two ends of the conductor is
Options
- A5 V
- B50 mV
- C5 mV
- D50 V
Correct answer
D. 50 V
Step-by-step solution
aligned & Induced emf, e = 1 2 ~B ^2 & = 1 2 0.2 10⁻⁴ (1)^2 5 & =0.5 10⁻⁴ ~V =50 V aligned