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MHT CET2012PhysicsElectromagnetic Induction

Two different coils have self inductance 8 mH and 2 mH . The current in both coils are increased at same constant rate. The ratio of the induced emf's in the coil is

Options

  1. A4: 1
  2. B1: 4
  3. C1: 2
  4. D2: 1

Correct answer

A. 4: 1

Step-by-step solution

The induced emf, e= L d i d t Here, L₁=8 mH =8 10⁻³ H and L₂=2 mH =2 10⁻³ H So, ratio of induced emfs, e₁ e₂ = L₁ d i d t L₂ d i d t = L₁ L₂ (since, current is increased at same rate) q e₂ = 8 10⁻³ H 2 10⁻³ H = 4 1

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