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MHT CET202611 April 2026Evening ShiftPhysicsElectrostaticsActual

If the radius of the spherical Gaussian surface is increased then the electric flux due to a point charge enclosed by the surface

Options

  1. Aincreases
  2. Bremains unchanged
  3. Cis zero
  4. Ddecreases

Correct answer

B. remains unchanged

Step-by-step solution

According to Gauss's law, the total electric flux through a closed surface is given by = q_ enclosed ₀ . The electric flux depends only on the net charge enclosed by the surface and is independent of the size or shape of the Gaussian surface. When the radius of the spherical Gaussian surface is increased, the charge enclosed by it remains the same. Therefore, the electric flux remains unchanged. Answer: remains unchanged

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