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MHT CET202611 April 2026Morning ShiftPhysicsElectrostaticsActual

Following figure indicates the electric potential V as a function through 4 regions on x-axis. Which of the following is correct for the electric field E in these regions?

Options

  1. AE₁ < E₂ < E₃ < E₄
  2. BE₂ = E₄ and E₁ < E₂
  3. CE₁ = E₃ and E₂ < E₄
  4. DE₁ > E₂ > E₃ > E₄

Correct answer

C. E₁ = E₃ and E₂ < E₄

Step-by-step solution

The relation between electric field E and electric potential V is given by E = - dV dx . The magnitude of the electric field is equal to the magnitude of the slope of the V-x graph. In regions 1 and 3, the potential V is constant. Therefore, the slope is zero, which means E₁ = 0 and E₃ = 0 . Thus, E₁ = E₃ . In region 2, the magnitude of the electric field is E₂ = | V x | = V_C - V_B x_C - x_B . In region 4, the magnitude of the electric field is E₄ = | V x | = V_D - V_E x_E - x_D = V_C - 0 x_E - x_D . From the give

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