MHT CET202611 April 2026Morning ShiftPhysicsElectrostaticsActual
Following figure indicates the electric potential V as a function through 4 regions on x-axis. Which of the following is correct for the electric field E in these regions?
Options
- AE₁ < E₂ < E₃ < E₄
- BE₂ = E₄ and E₁ < E₂
- CE₁ = E₃ and E₂ < E₄
- DE₁ > E₂ > E₃ > E₄
Correct answer
C. E₁ = E₃ and E₂ < E₄
Step-by-step solution
The relation between electric field E and electric potential V is given by E = - dV dx . The magnitude of the electric field is equal to the magnitude of the slope of the V-x graph. In regions 1 and 3, the potential V is constant. Therefore, the slope is zero, which means E₁ = 0 and E₃ = 0 . Thus, E₁ = E₃ . In region 2, the magnitude of the electric field is E₂ = | V x | = V_C - V_B x_C - x_B . In region 4, the magnitude of the electric field is E₄ = | V x | = V_D - V_E x_E - x_D = V_C - 0 x_E - x_D . From the give