Charges of 2 C and -3 C are placed at two points A and B separated by distance of 1 m . The distance of the point from A where net potential is zero is

Step-by-step solution

Let charges be q_A = 2 , C and q_B = -3 , C separated by distance d = 1 , m . To find a point with zero net electric potential, consider possible regions and use V = kq r formulation. Case 1: Between the charges Let point P be at distance x from A, so distance from B is 1 - x . The net potential V_P = kq_A x + kq_B 1 - x = 0 yields 2 x = 3 1 - x , resulting in 2(1 - x) = 3x and x = 0.4 , m . This point lies between A and B. Case 2: Outside the charges Let P be left of A with distance x to A and 1 + x to B. Setting