The electric field intensity near a conducting surface having uniform surface charge density ' ' is given by ( ₀= permittivity of free space)

Step-by-step solution

Electric field near a conducting surface A Gaussian pillbox with one face inside the conductor and the other just outside provides the appropriate surface for applying Gauss's law. The electric field inside the conductor is zero, while the field outside is perpendicular to the surface. The flux through the curved surface is zero due to the parallel alignment with the field lines. Only the external end face contributes to the flux, giving = EA for area A . The enclosed charge is q_ enc = A . Applying Gauss's law: EA