A hollow cylinder has a charge ' q ' coulomb within it. If ' ' is the electric flux in unit of V-m associated with the curved surface C, the flux linked with the plane surface 'A' in unit of V-m will be [ ₀= . permittivity of free space ]

Step-by-step solution

Gauss’s law establishes that the total electric flux _ total through any closed surface equals the enclosed charge q divided by the permittivity of free space ₀ : _ total = q ₀ For a hollow cylinder acting as the closed surface, the total flux is the sum through its constituent surfaces: _ total = _A + _B + _C , where _A and _B pertain to the planar end faces and _C to the curved surface. Given _C = , and by symmetry, the flux through the two identical plane surfaces is equal, _A = _B . Substituting yields: q ₀ = 2