The electric potential ' V ' is given as a function of distance ' x ' (metre) by V= (4 x^2+8 x-3 ) V . The value of electric field at x=0.5 ~m , in V / m is

Step-by-step solution

The electric potential V is given by V = 4x^2 + 8x - 3 volts. Since the electric field E = - dV dx , we compute the derivative: dV dx = 8x + 8 Thus, E = -(8x + 8) volts per meter. Evaluating at x = 0.5 meters, E = -(8 0.5 + 8) = -(4 + 8) = -12 V/m The electric field at x = 0.5 m is -12 V/m , corresponding to option B.