Two point charges +8 q and -2 q are located at x=0 and x= L respectively. The location of a point on the x -axis from the origin, at which the net electric field due to these two point charges is zero is

Step-by-step solution

Let ' A ' be the point at a distance r from -2 q and at (L+r) from +8 q where net electric field is zero. E ₁= E ₂ array ll & K (8 q) (L+r)^2 = K(2 q) r^2 & 4 (L+r)^2 = 1 r^2 & 2 r=L+r & r=L & A=L+L=2 L array