MHT CET202411 May 2024Morning ShiftPhysicsElectrostaticsActual
A small particle carrying a negative charge of 1.6 10⁻¹⁹ C is suspended in equilibrium between two horizontal metal plates 8 cm apart having a potential difference of 980 V across them. The mass of the particle is [ g =9.8 ~m / s ^2 ]
Options
- A2 10⁻¹⁶ ~kg
- B2.2 10⁻¹⁶ ~kg
- C20 10⁻¹⁶ ~kg
- D4 10⁻¹⁶ ~kg
Correct answer
A. 2 10⁻¹⁶ ~kg
Step-by-step solution
Magnitude of the force due to the electric field F = qE = qV ~d This should be equal to the weight of the particle aligned & mg = qV ~d & aligned m & = qV gd = 1.6 10⁻¹⁹ 980 9.8 10⁻² 8 & =2 10⁻¹⁶ ~kg aligned aligned