Two point charges (A and B)+4 q and -4 q are placed along a line separated by a distance ' r '. Force acting between them is F. If 25 % of charge from point A is transferred to that at point B , the force between the charges now becomes

Step-by-step solution

Force acting between given charges +4 q and -4 q is, F= -16 q^2 4 ₀ r^2 ...(i) When 25 % of charges ảre transferred, charge on point A becomes, q₁=+4 q-0.25(+4 q)=+3 q Charge on point B becomes, q₂=-4 q+0.25(+4 q)=-3 q The new force between points A and B will be, F ^ = (3 q ) (-3 q ) 4 ₀ r ^2 = -9 q ^2 4 ₀ r ^2 Multiplying and dividing by 16 , F^ = 9 16 ( -16 q^2 4 ₀ r^2 )= 9 16 F [ From (i)]