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MHT CET202410 May 2024Morning ShiftPhysicsElectrostaticsActual

Two point charges +10 q and -4 q are located at x =0 and x = L respectively. What is the location of a point on the x -axis from the origin, which the net electric field due to these two point charges is zero? ( r = required distance )

Options

  1. Ar = 2 5 - 2 right to pt.B
  2. Br = 2 5 - 2 left to pt.A
  3. Cr = 2 5 + 2 right to pt.B
  4. Dr = 2 5 + 2 left to pt.A

Correct answer

A. r = 2 5 - 2 right to pt.B

Step-by-step solution

Let ' Q ' be the point at a distance r from -4 q and ( L + r ) from 10 q . wherein net electric field is zero. aligned & E₁=E₂ & K(10 q) (L+r)^2 = K(4 q) r^2 aligned aligned & 10 ~L + r = 2 r & 5 2 ~L + r = 2 2 r = 2 r & 5 2 r =2( ~L + r ) & 5 2 r = 2 2 ( ~L + r ) & 5 r = 2 ~L + 2 r & 5 - 2 r = 2 ~L & r = 2 5 - 2 aligned If B is position of charge -4 q then point Q is r= 2 5 - 2 to the right of B

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