A regular hexagon of side 10 cm has a charge 1 C at each of its vertices. The potential at the centre of hexagon is [ 1 4 ₀ =9 10^9 . SI unit ]

Step-by-step solution

Potential at the centre of hexagon aligned V₀ & =V_A+V_B+V_C+V_D+V_E+V_F & = 1 4 ₀ [ q O A + q O B + q O C + q O D + q O E + q O F ] aligned For a hexagon, distance from centre to vertices is equal to length of side. aligned OA = OB = OC = OD = OE = OF & =10 ~cm & =0.1 ~m aligned aligned V _ & = 1 4 ₀ q 0.1 (6) & =9 10^9 (1 10⁻⁶ ) 6 0.1 & =5.4 10^5 volt aligned