MHT CET20243 May 2024Morning ShiftPhysicsElectrostaticsActual
Two equal point charges ' q ' each exert a force ' F ' on each other, when they are placed distance ' x ' apart in air. When the same charges are placed distance ' y ' apart in a medium of dielectric constant ' k ', they exert the same force. The ratio of distance ' y ' to ' x ' is equal to
Options
- A1 k
- Bk
- Ck 2
- D2 k
Correct answer
A. 1 k
Step-by-step solution
Force between the two charges in air, F ₁= 1 4 ₀ q q x ^2 Force between the two charges when in a medium of dielectric constant k, aligned & F ₂= 1 4 ₀ k q q y ^2 & ~F ₁ ~F ₂ = 1 4 ₀ q ^2 x ^2 4 ₀ k y ^2 q ^2 aligned array ll 1 & =k y^2 x^2 ( F₁=F₂ ) & y x = 1 k array