The electric field intensity on the surface of a solid charged sphere of radius ' r ' and volume charge density ' ' is ( ₀= permittivity of free space )

Step-by-step solution

According to Gauss' theorem, = E A = q _ enc ₀ But, q _ enc = volume q _ enc = ( 4 3 r ^3 ) And area is A=4 r^2 aligned & E (4 r ^2 )= ( 4 3 r ^3 ) ₀ & E = r 3 ₀ aligned