The work done in rotating a dipole placed parallel to the electric field through 180^ is 'w'. So the work done in rotating it through 60^ is ( 0^ =1, 60^ = 1 2 , 180^ =-1 )

Step-by-step solution

Work done W = p E [ ₀- ] Given, W = pE (1- 180^ ) W = pE (1- 180^ ) aligned & W = pE (1-(-1)) & W =2 pE & pE = 1 2 ~W aligned When =60^ aligned & W ^ = pE (1- 60^ ) & W ^ = pE (1- 1 2 ) & W ^ = 1 2 pE & W ^ = 1 2 1 2 ~W & ~W ^ = 1 4 ~W aligned