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MHT CET202313 May 2023Morning ShiftPhysicsElectrostaticsActual

Two cells E ₁ and E ₂ having equal EMF ' E ' and internal resistances r₁ and r₂ (r₁>r₂ ) respectively are connected in series. This combination is connected to an external resistance ' R '. It is observed that the potential difference across the cell E₁ becomes zero. The value of ' R ' will be

Options

  1. Ar₁-r₂
  2. Br ₁+ r ₂
  3. Cr ₁- r ₂ 2
  4. Dr₁+r₂ 2

Correct answer

A. r₁-r₂

Step-by-step solution

The total current in the circuit is I= 2 E r₁+r₂+R ....(Given cells are in series, E + E =2 E ) Now the potential drop across the first cell is array ll & V ₁= E - Ir ₁=0 & E - ( 2 E r ₁+ r ₂+ R ) r ₁=0 & 2 E r ₁+ r ₂+ R = E r ₁ 2 r ₁= r ₁+ r ₂+ R & R = r ₁- r ₂ array

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