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MHT CET202123 Sep 2021Evening ShiftPhysicsElectrostaticsActual

A charged spherical conductor has radius ' r '. The potential difference between its surface and a point at a distance ' 3 r ' from the center is ' V ' The electric intensity at a distance ' 3 r ' from the centre of the conductor is

Options

  1. AV 8 r
  2. BV 2 r
  3. CV 4 r
  4. DV 6 r

Correct answer

D. V 6 r

Step-by-step solution

aligned & V = q 4 ₀ r [1- 1 3 ]= 2 3 q 4 ₀ r & E = q 4 ₀ 1 (3 r )^2 = q 4 ₀ 1 9 r ^2 & E V = 1 6 r & E = V 6 r aligned

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