MHT CET202123 Sep 2021Evening ShiftPhysicsElectrostaticsActual
Two charge metallic spheres are joined by a very thin metal wire. If the radius of the larger sphere is four times that of the smaller sphere, the electric field near the larger sphere is
Options
- Atwice that near the smaller sphere
- Bquarter of that near the smaller sphere
- Csame as that near the smaller sphere
- Dhalf of that near smaller sphere
Correct answer
B. quarter of that near the smaller sphere
Step-by-step solution
Since the spheres are joined by a metal wire, their potentials will be same. Let the radius of the smaller sphere be r₁ and the radius of the larger sphere be r₂=4 r₁ the v = 1 4 ₀ q ₁ r ₁ = 1 4 ₀ q ₂ r ₂ q ₂ q ₁ = r ₂ r ₁ The electric field near the surface of spheres are given by aligned & E ₁= 1 4 ₀ q ₁ r ₁^2 and E ₂= 1 4 ₀ q ₂ r ₂^2 & E ₂ E ₁ = q ₂ q ₁ r ₁^2 r ₂^2 = r ₂ r ₁ r ₁^2 r ₂^2 = r ₁ r ₂ = 1 4 aligned