MHT CET202121 Sep 2021Evening ShiftPhysicsElectrostaticsActual
A hollow metal sphere has a radius ' r '. The potential difference between a point on its surface and at a point at a distance ' 3 r ' from its center is ' V '. The electric intensity at the distance ' 3 r ' from the center of the sphere will be
Options
- AV 3 r
- B3 Vr
- CV r
- DV 6 r
Correct answer
D. V 6 r
Step-by-step solution
Let the charge on the sphere is Q. aligned & V = kQ r - kQ 3 r = 2 kQ 3 r & kQ = 3 Vr 2 & E = kQ (3 r )^2 = 1 (3 r )^2 3 Vr 2 = V 6 r aligned