MHT CET202120 Sep 2021Evening ShiftPhysicsElectrostaticsActual
A spherical conducting shell of inner radius ' r₁ ' and outer radius ' r₂ ' has a charge ' Q '. A charge -q is placed at the center of the shell. The surface charge density on the inner and outer surface of the shell will be
Options
- Aq 4 r ₁^2 and Q - q 4 r ₂^2
- Bq 4 r ₁^2 and Q 4 r ₂^2
- C- q 4 r ₁^2 and Q + q 4 r ₂^2
- Dzero and Q - q 4 r ₂^2
Correct answer
A. q 4 r ₁^2 and Q - q 4 r ₂^2
Step-by-step solution
Due to charge -q at the center of the shell, a charge q will be induced on the inner surface and -q on the outer surface. The charge on outer surface will become Q-q . Hence surface charge densities will be q 4 r ₁^2 and Q - q 4 r ₂^2