MHT CET2011PhysicsElectrostatics
Three particles, each having a charge of 10 C are placed at the corners of an equilateral triangle of side 10 cm. The electrostatic potential energy of the system is ( . Given . 1 4 ₀ =9 10⁹ ~N - m ² C ² )
Options
- AZero
- B27 ~J
- C100 ~J
Correct answer
C. 100 ~J
Step-by-step solution
For a pair of charges array c U= 1 4 ₀ q₁ q₂ r U_ system = 1 4 ₀ [ 10 10⁻⁶ 10 10⁻⁶ 10 / 100 . + 10 10⁻⁶ 10 10⁻⁶ 10 / 100 .+ 10 10⁻⁶ 10 10⁻⁶ 10 / 100 ] =3 9 10⁹ 100 10⁻¹² 100 10 =27 ~J array