MHT CET2009PhysicsElectrostatics
If the linear charge density of a cylinder is 4 Cm ⁻¹ then electric field intensity at point 3.6 ~cm from axis is
Options
- A4 10⁵ NC ⁻¹
- B2 10⁶ NC ⁻¹
- C8 10⁷ NC ⁻¹
- D12 10⁷ NC ⁻¹
Correct answer
B. 2 10⁶ NC ⁻¹
Step-by-step solution
For a charged cylinder aligned E &= 2 ₀ r = 4 10⁻⁶ 18 10⁹ 3.6 10⁻² &=2 10⁶ NC ⁻¹ aligned