Consider the following five samples of substances: A. 88 g of CO ₂ B. 96 g of O ₂ C. 34 g of NH ₃ D. 36 g of H ₂ O E. 40 g of Ne Which of the given samples contain an identical total number of atoms? (Given atomic masses in u : H =1 , C =12 , N =14 , O =16 , Ne =20 )

Step-by-step solution

Molar mass of CO ₂ = 12 + 2 16 = 44 g/mol Moles of CO ₂ = 88 44 = 2 moles Total atoms in A = 2 3 N_A = 6 N_A Molar mass of O ₂ = 2 16 = 32 g/mol Moles of O ₂ = 96 32 = 3 moles Total atoms in B = 3 2 N_A = 6 N_A Molar mass of NH ₃ = 14 + 3 1 = 17 g/mol Moles of NH ₃ = 34 17 = 2 moles Total atoms in C = 2 4 N_A = 8 N_A Molar mass of H ₂ O = 2 1 + 16 = 18 g/mol Moles of H ₂ O = 36 18 = 2 moles Total atoms in D = 2 3 N_A = 6 N_A Molar mass of Ne = 20 g/mol Moles of Ne = 40 20 = 2 moles Total atoms in E = 2 1 N_A = 2 N_