NEET2026BiologyChapterActual
Match List I with List II regarding the structural dimensions and packaging of DNA: List I List II A Pitch of the DNA helix 1 2.2 m B Distance between two consecutive base pairs 2 1.36 mm C Total length of DNA in a typical mammalian cell 3 3.4 nm D Total length of DNA in Escherichia coli 4 0.34 nm Choose the correct answer from the options given below:
Options
- A(A) - 4, (B) - 3, (C) - 1, (D) - 2
- B(A) - 3, (B) - 4, (C) - 2, (D) - 1
- C(A) - 3, (B) - 4, (C) - 1, (D) - 2
- D(A) - 4, (B) - 3, (C) - 2, (D) - 1
Correct answer
C. (A) - 3, (B) - 4, (C) - 1, (D) - 2
Step-by-step solution
The pitch of the B-DNA helix is 3.4 nm. The distance between two consecutive base pairs in a B-DNA helix is 0.34 nm. The total length of DNA in a typical mammalian cell is calculated by multiplying the total number of base pairs ( 6.6 10⁹ bp) by the distance between two consecutive base pairs ( 0.34 10⁻⁹ m/bp), which gives approximately 2.2 m. The total length of DNA in Escherichia coli is given as 1.36 mm. Therefore, the correct matching is (A) - 3, (B) - 4, (C) - 1, (D) - 2. Answer: (A) - 3, (B) - 4, (C) - 1, (D)