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JEE MainPhysicsCurrent Electricity

A 15 V battery with an internal resistance of 1 is connected across a parallel combination of two branches. The upper branch consists of a 4 resistor and a 2 resistor in series. The lower branch consists of a 2 resistor and a 10 resistor in series. The 4 and 2 resistors of the upper and lower branches respectively are connected to the positive terminal side of the parallel combination. A 5 F capacitor is connected be

Correct answer

90

Step-by-step solution

In steady state, the capacitor acts as an open circuit, so no current flows through its branch. The equivalent resistance of the upper branch is R₁ = 4 + 2 = 6 . The equivalent resistance of the lower branch is R₂ = 2 + 10 = 12 . The equivalent resistance of the parallel combination is R_p = 6 12 6 + 12 = 4 . The total resistance of the circuit is R_ eq = R_p + r = 4 + 1 = 5 . The total current drawn from the battery is I = 15 5 = 3 A . The potential difference across the parallel combination is V_p = I R_p = 3 4 =

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