The mole fraction of glucose in an aqueous solution is 1 41 . What is the mass percentage (w/w) of glucose in the solution? [Given: Molar mass of glucose is 180 g mol ⁻¹ and that of water is 18 g mol ⁻¹ ]

Step-by-step solution

Let the total number of moles in the solution be 41 mol. Moles of glucose, n_ glucose = 1 mol Moles of water, n_ water = 41 - 1 = 40 mol Mass of glucose = 1 180 = 180 g Mass of water = 40 18 = 720 g Total mass of the solution = 180 + 720 = 900 g Mass percentage of glucose = ( Mass of glucose Total mass of solution ) 100 Mass percentage = ( 180 900 ) 100 = 20 % Answer: 20 %