JEE MainChemistrySolutions
An aqueous solution of volume 200 mL is prepared by dissolving a polymer of molar mass 150000 g mol ⁻¹ . If the osmotic pressure of this solution at 300 K is found to be 4.98 10⁻³ bar , the mass of the polymer dissolved is ________ g . (Given: R = 0.083 L bar K ⁻¹ mol ⁻¹ )
Correct answer
6
Step-by-step solution
The osmotic pressure is given by the formula: = CRT = w MV RT Where: = 4.98 10⁻³ bar M = 150000 g mol ⁻¹ V = 200 mL = 0.2 L R = 0.083 L bar K ⁻¹ mol ⁻¹ T = 300 K Rearranging for the mass of the polymer w : w = M V RT Substituting the values: w = 4.98 10⁻³ 150000 0.2 0.083 300 w = 149.4 24.9 = 6 g Answer: 6