JEE MainPhysicsCurrent Electricity
A galvanometer having a coil resistance of 50 is converted into a voltmeter of range 0 to 10 V by connecting a series resistance of 4950 . What is the value of the shunt resistance required to convert the same galvanometer into an ammeter of range 0 to 10 mA ?
Options
- A10
- B200
- C12.5
- D5.5
Correct answer
C. 12.5
Step-by-step solution
Let the full-scale deflection current of the galvanometer be I_g . For the voltmeter conversion, the total resistance is R_v = G + R . Using Ohm's law, V = I_g(G + R) 10 = I_g(50 + 4950) 10 = I_g(5000) I_g = 2 10⁻³ A = 2 mA To convert the galvanometer into an ammeter of range I = 10 mA , a shunt resistance S is connected in parallel. The formula for the shunt resistance is S = I_g G I - I_g S = 2 50 10 - 2 = 100 8 = 12.5 Answer: 12.5