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JEE MainPhysicsCurrent Electricity

In a DC circuit, a battery is connected in series with a 2 resistor, which leads to a node C. From node C, two parallel branches connect to the negative terminal of the battery (ground). The first branch consists of a 4 resistor connected to a node D, followed by an ideal ammeter connecting node D to ground. The second branch consists of a 4 resistor connected to a node E, followed by a 2 resistor connecting node E t

Options

  1. A60 C
  2. B40 C
  3. C20 C
  4. D12 C

Correct answer

C. 20 C

Step-by-step solution

In the steady state, the capacitor is fully charged and acts as an open circuit, so no current flows through the branch connecting node D and node E. The ideal ammeter has zero resistance, so node D is at ground potential ( V_D = 0 V ). The ammeter reads the current flowing through the first branch, which is 1.5 A . The potential at node C can be found using the voltage drop across the 4 resistor in the first branch: V_C - V_D = I₁ 4 V_C - 0 = 1.5 4 = 6 V . The second branch (from node C to ground) has a total resi

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