An ammeter is constructed by connecting a shunt in parallel with a galvanometer of resistance G . If the equivalent resistance of the ammeter is G 50 , the ratio of the current passing through the shunt to the current passing through the galvanometer is:

Step-by-step solution

Let S be the resistance of the shunt. The equivalent resistance of the ammeter is given by the parallel combination of G and S : R_A = SG S+G Given that R_A = G 50 , we have: SG S+G = G 50 50S = S + G 49S = G G S = 49 In a parallel circuit, the potential drop across both branches is equal. Therefore, I_s S = I_g G , which gives: I_s I_g = G S Substituting the value of G S , we get: I_s I_g = 49 Answer: 49