Complete reductive ozonolysis of 960 mg of a hydrocarbon C yields solely 2,6 -heptanedione as the product. The volume of H ₂ gas (in mL ) that would be consumed by 960 mg of C during complete catalytic hydrogenation at STP ( 1 atm , 273 K )

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Complete reductive ozonolysis of 960 mg of a hydrocarbon C yields solely 2,6 -heptanedione as the product. The volume of H ₂ gas (in mL ) that would be consumed by 960 mg of C during complete catalytic hydrogenation at STP ( 1 atm , 273 K ) is

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Correct answer: 224

Since the ozonolysis of hydrocarbon C yields a single product containing two carbonyl groups, C must be a monocycloalkene. The product is 2,6 -heptanedione: CH ₃- C(=O) - CH ₂- CH ₂- CH ₂- C(=O) - CH ₃ . To find the structure of C, we connect the two carbonyl carbons (C2 and C6) to form a double bond. This creates a five-membered ring with methyl groups on the two carbons of the double bond. Thus, hydrocarbon C is 1,2 -dimethylcyclopentene. The molecular formula of 1,2 -dimethylcyclopentene is C ₇ H ₁₂ . Molar mass

Complete reductive ozonolysis of 960 mg of a hydrocarbon C yields solely 2,6 -heptanedione as the product. The volume of H ₂ gas (in mL ) that would be consumed by 960 mg of C during complete catalytic hydrogenation at STP ( 1 atm , 273 K ) is

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