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An alkene 'P' with the molecular formula C ₈ H ₁₆ undergoes reductive ozonolysis to yield two different carbonyl compounds: a ketone 'Q' and a straight-chain aldehyde 'R'. When 'P' is treated with hot acidic KMnO ₄ , it yields the same ketone 'Q' along with a carboxylic acid 'S'. If 'Q' and 'S' contain an equal number of carbon atoms, the IUPAC name of alkene 'P' is

Options

  1. A4-methylhept-3-ene
  2. B2,4-dimethylhex-3-ene
  3. C3-methylhept-3-ene
  4. D3,4-dimethylhex-3-ene

Correct answer

C. 3-methylhept-3-ene

Step-by-step solution

Given that alkene 'P' ( C ₈ H ₁₆ ) undergoes reductive ozonolysis to give a ketone 'Q' and a straight-chain aldehyde 'R', 'P' must be a trisubstituted alkene. Upon vigorous oxidation with hot acidic KMnO ₄ , the aldehyde part is oxidized to a carboxylic acid 'S', while the ketone 'Q' remains unchanged. Since 'P' has 8 carbon atoms and 'Q' and 'S' have an equal number of carbon atoms, both 'Q' and 'S' must have 4 carbon atoms each. The 4-carbon ketone 'Q' is butan-2-one ( CH ₃ COCH ₂ CH ₃ ). The 4-carbon carboxylic

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