A polymer solution is prepared by dissolving 1.2 g of the polymer in 300 mL of water at 27^ C . If the osmotic pressure of the solution is measured to be 332 Pa , the molar mass of the polymer is _____ kg mol ⁻¹ . (Given: R = 0.083 L bar K

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A polymer solution is prepared by dissolving 1.2 g of the polymer in 300 mL of water at 27^ C . If the osmotic pressure of the solution is measured to be 332 Pa , the molar mass of the polymer is _____ kg mol ⁻¹ . (Given: R = 0.083 L bar K ⁻¹ mol ⁻¹ , 1 bar = 10^5 Pa )

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Correct answer: 30

Given: Mass of polymer, m = 1.2 g Volume of solution, V = 300 mL = 0.3 L Temperature, T = 27^ C = 300 K Osmotic pressure, = 332 Pa = 332 10⁻⁵ bar = 3.32 10⁻³ bar The osmotic pressure is given by the formula: = m M RT V Rearranging for molar mass M : M = mRT V Substituting the values: M = 1.2 0.083 300 3.32 10⁻³ 0.3 M = 29.88 0.000996 = 30000 g mol ⁻¹ Converting to kg mol ⁻¹ : M = 30 kg mol ⁻¹ Answer: 30

A polymer solution is prepared by dissolving 1.2 g of the polymer in 300 mL of water at 27^ C . If the osmotic pressure of the solution is measured to be 332 Pa , the molar mass of the polymer is _____ kg mol ⁻¹ . (Given: R = 0.083 L bar K ⁻¹ mol ⁻¹ , 1 bar = 10^5 Pa )

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