JEE MainMathematicsStraight Lines
Let B and C be two points on the line 4x + 3y = 0 such that B and C are symmetric with respect to the origin. Suppose A is a point in the first quadrant on the line 2x + y = k such that ABC is an equilateral triangle. If the area of ABC is 75 3 , then the value of k is
Options
- A33
- B30
- C22 3
- D-33
Correct answer
A. 33
Step-by-step solution
Since B and C lie on 4x + 3y = 0 and are symmetric with respect to the origin, the origin (0,0) is the midpoint of BC . In an equilateral triangle, the median is also the altitude. Thus, the altitude from A to BC lies on the perpendicular bisector of BC , which passes through the origin. The equation of the perpendicular bisector is 3x - 4y = 0 . Let the coordinates of A be (4t, 3t) . The length of the altitude h is the distance from A to the origin: h = (4t)^2 + (3t)^2 = 5|t| . The area of an equilateral triangle