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JEE MainPhysicsCurrent Electricity

In a DC circuit, a battery of unknown voltage V is connected in series with a 2 resistor, which leads to a node A. From node A, the circuit splits into two parallel branches that eventually connect to the negative terminal (ground). The first branch contains a 6 resistor connected directly to ground. The second branch contains a 3 resistor leading to a node C, which then splits into two parallel 6 resistors that reco

Options

  1. A10 V
  2. B20 V
  3. C12 V
  4. D44 V

Correct answer

B. 20 V

Step-by-step solution

In the steady state, the capacitor acts as an open circuit, so no current flows through the diagonal branch connecting node A and node D. The ammeter at node D measures the total current flowing through the second branch. The equivalent resistance of this second branch (from node A to node D) is the 3 resistor in series with the parallel combination of the two 6 resistors: R₂ = 3 + 6 6 6 + 6 = 3 + 3 = 6 . Since the current through this branch is 2 A , the potential at node A is: V_A = I₂ R₂ = 2 6 = 12 V . The first

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