A battery of 50 V is connected in series with a resistor of 88 and a non-ideal ammeter of resistance 60 . A shunt resistance S is connected in parallel with the ammeter. If the reading of the ammeter is 100 mA, the value of S is _____ .

Step-by-step solution

Let the current through the ammeter be I_A = 100 mA = 0.1 A. The voltage drop across the ammeter is: V_A = I_A R_A = 0.1 60 = 6 V Since the ammeter and the shunt are in parallel, the voltage drop across the shunt is also 6 V, and the total voltage drop across the parallel combination is 6 V. The remaining voltage from the battery drops across the series resistor: V_R = 50 - 6 = 44 V The total current I flowing through the main circuit (and the series resistor) is: I = V_R R = 44 88 = 0.5 A Applying Kirchhoff's Curr