JEE MainChemistryRedox Reactions
Chlorine gas reacts with hot and concentrated sodium hydroxide solution to form sodium chloride, sodium chlorate, and water. If the molar mass of Cl ₂ is M , what is the equivalent mass of Cl ₂ in this disproportionation reaction?
Options
- AM 2
- BM 10
- C5M 3
- D3M 5
Correct answer
D. 3M 5
Step-by-step solution
The reaction of chlorine with hot and concentrated NaOH is: 3 Cl ₂ + 6 OH ^- 5 Cl ^- + ClO ₃^- + 3 H ₂ O In this reaction, Cl ₂ undergoes disproportionation. Oxidation half-reaction: Cl ₂ 2 ClO ₃^- The change in oxidation state of Cl is from 0 to +5 . Number of electrons lost per Cl ₂ molecule, n₁ = 2 5 = 10 . Reduction half-reaction: Cl ₂ 2 Cl ^- The change in oxidation state of Cl is from 0 to -1 . Number of electrons gained per Cl ₂ molecule, n₂ = 2 1 = 2 . For a disproportionation reaction, the net n-factor ( n