JEE MainPhysicsCurrent Electricity
A galvanometer of resistance G is converted into an ammeter of range I by connecting a shunt of resistance S . To double the range of this ammeter to 2I , an additional resistor R is connected in parallel with the existing shunt. The value of R is:
Options
- AS
- BS 2
- CGS G+S
- DGS 2(G+S)
Correct answer
C. GS G+S
Step-by-step solution
For the initial ammeter of range I , the maximum current I_g through the galvanometer satisfies: I = I_g + I_s = I_g + I_g G S = I_g (1 + G S ) Let S_ eq be the new equivalent shunt resistance when R is connected in parallel with S . For the new range 2I , we have: 2I = I_g (1 + G S_ eq ) Substituting the expression for I into the second equation: 2 (1 + G S ) = 1 + G S_ eq 2 + 2G S = 1 + G S_ eq G S_ eq = 1 + 2G S 1 S_ eq = 1 G + 2 S Since S_ eq is the parallel combination of S and R , we know 1 S_ eq = 1 S + 1 R