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JEE MainChemistryRedox Reactions

A student performs two separate redox titrations using acidified KMnO ₄ as the titrant. For Reductant A, the decolorization of the first few drops is very slow at room temperature, requiring the flask to be heated to about 60^ C , after which the reaction speeds up. For Reductant B, the decolorization is instantaneous at room temperature, and the lab manual explicitly warns against heating to prevent aerial oxidation

Options

  1. AReductant A: Mohr's salt, Reductant B: Oxalic acid, Auto-catalyst: Mn ²⁺
  2. BReductant A: Oxalic acid, Reductant B: Mohr's salt, Auto-catalyst: MnO ₄⁻
  3. CReductant A: Oxalic acid, Reductant B: Mohr's salt, Auto-catalyst: Mn ²⁺
  4. DReductant A: Oxalic acid, Reductant B: Mohr's salt, Auto-catalyst: CO ₂

Correct answer

C. Reductant A: Oxalic acid, Reductant B: Mohr's salt, Auto-catalyst: Mn ²⁺

Step-by-step solution

The titration of oxalic acid with KMnO ₄ is slow at room temperature due to high activation energy, so it requires initial heating to about 60^ C . Thus, Reductant A is oxalic acid. Once the reaction begins, the Mn ²⁺ ions formed act as an auto-catalyst, speeding up the subsequent decolorization. The titration of Mohr's salt (FAS) with KMnO ₄ is fast at room temperature. Heating is avoided because the active species, Fe ²⁺ , can undergo aerial oxidation to Fe ³⁺ at elevated temperatures, which introduces an error i

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