JEE MainChemistryHydrocarbons
An aromatic, oxygen-containing compound 'X' gives a characteristic violet colour with neutral FeCl ₃ solution. When 'X' is heated with zinc dust, it forms a hydrocarbon 'Y'. Compound 'Y' on treatment with oleum gives 'Z'. Compound 'Z' on fusion with NaOH at high temperature followed by acidification regenerates 'X'. Identify the compounds 'Y' and 'Z' respectively.
Options
- ACyclohexane and cyclohexanesulfonic acid
- BBenzene and benzenesulfonic acid
- CBenzene and o -hydroxybenzenesulfonic acid
- DBenzene and benzoic acid
Correct answer
B. Benzene and benzenesulfonic acid
Step-by-step solution
The characteristic violet colour with neutral FeCl ₃ solution indicates that compound 'X' is a phenol. Heating phenol (X) with zinc dust causes its reduction to benzene (compound 'Y'). Benzene undergoes sulfonation when treated with oleum (fuming sulfuric acid) to form benzenesulfonic acid (compound 'Z'). Fusion of benzenesulfonic acid with NaOH followed by acidification replaces the - SO ₃ H group with an - OH group, regenerating phenol (X). Thus, Y is benzene and Z is benzenesulfonic acid. Answer: Benzene and ben