A 30 mL sample of 0.1 M potassium permanganate ( KMnO ₄ ) solution completely reacts with a 0.1 M solution of ferrous oxalate ( FeC ₂ O ₄ ) in an acidic medium. The volume of the ferrous oxalate solution oxidized is mL.

Step-by-step solution

In an acidic medium, KMnO ₄ acts as an oxidizing agent and reduces to Mn ²⁺ : MnO ₄^- + 8 H ^+ + 5 e ^- Mn ²⁺ + 4 H ₂ O The n-factor of KMnO ₄ is 5 . In ferrous oxalate ( FeC ₂ O ₄ ), both the ferrous ion ( Fe ²⁺ ) and the oxalate ion ( C ₂ O ₄²⁻ ) undergo oxidation: Fe ²⁺ Fe ³⁺ + e ^- C ₂ O ₄²⁻ 2 CO ₂ + 2 e ^- Total moles of electrons lost per mole of FeC ₂ O ₄ = 1 + 2 = 3 . Thus, the n-factor of FeC ₂ O ₄ is 3 . Equating the milliequivalents of both reactants: Equivalents of KMnO ₄ = Equivalents of FeC ₂ O ₄ M₁ V