MHT CET Medical202622 April 2026Evening ShiftBiologyPrinciples of Inheritance and VariationActual
Match List I with List II List I (Organisms) List II (Chromosome number) (A). Roundworm (I). 40 (B). Mouse (II). 32 (C). Fruit fly (III). 12 (D). Yeast (IV). 8 Choose the correct answer from the options given below:
Options
- A(A) - (I), (B) - (II), (C) - (III), (D) - (IV)
- B(A) - (II), (B) - (IV), (C) - (I), (D) - (III)
- C(A) - (I), (B) - (II), (C) - (IV), (D) - (III)
- D(A) - (III), (B) - (I), (C) - (IV), (D) - (II)
Correct answer
D. (A) - (III), (B) - (I), (C) - (IV), (D) - (II)
Step-by-step solution
The correct chromosome numbers (diploid, 2n ) for the given organisms are as follows: Roundworm (Caenorhabditis elegans) has 12 chromosomes. Mouse (Mus musculus) has 40 chromosomes. Fruit fly (Drosophila melanogaster) has 8 chromosomes. Yeast (Saccharomyces cerevisiae) has 32 chromosomes. Therefore, the correct matching is (A) - (III), (B) - (I), (C) - (IV), (D) - (II). Answer: (A) - (III), (B) - (I), (C) - (IV), (D) - (II)